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=-5C^2+750
We move all terms to the left:
-(-5C^2+750)=0
We get rid of parentheses
5C^2-750=0
a = 5; b = 0; c = -750;
Δ = b2-4ac
Δ = 02-4·5·(-750)
Δ = 15000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$C_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$C_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{15000}=\sqrt{2500*6}=\sqrt{2500}*\sqrt{6}=50\sqrt{6}$$C_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-50\sqrt{6}}{2*5}=\frac{0-50\sqrt{6}}{10} =-\frac{50\sqrt{6}}{10} =-5\sqrt{6} $$C_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+50\sqrt{6}}{2*5}=\frac{0+50\sqrt{6}}{10} =\frac{50\sqrt{6}}{10} =5\sqrt{6} $
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